Find the output of the following program.

void main()

{

printf(“sizeof (void *) = %d \n“, sizeof( void *));

            printf(“sizeof (int *)    = %d \n”, sizeof(int *));

            printf(“sizeof (double *)  = %d \n”, sizeof(double *));

            printf(“sizeof(struct unknown *) = %d \n”, sizeof(struct unknown *));

            }

Answer            :

sizeof (void *) = 2

sizeof (int *)    = 2

sizeof (double *)  =  2

sizeof(struct unknown *) =  2

Explanation:

The pointer to any type is of same size.